Manu: polished II B
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@ -15,7 +15,7 @@
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\newcommand{\alert}[1]{\textcolor{red}{#1}}
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\newcommand{\alert}[1]{\textcolor{red}{#1}}
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\usepackage[normalem]{ulem}
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\usepackage[normalem]{ulem}
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\newcommand{\titou}[1]{\textcolor{red}{#1}}
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\newcommand{\titou}[1]{\textcolor{red}{#1}}
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\newcommand{\manu}[1]{\textcolor{blue}{#1}}
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\newcommand{\manu}[1]{\textcolor{blue}{Manu: #1}}
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\newcommand{\trashPFL}[1]{\textcolor{red}{\sout{#1}}}
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@ -392,19 +392,23 @@ Eq.~(\ref{eq:excited_ener_level_gs_lim})].
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For implementation purposes, we will use in the rest of this work
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For implementation purposes, we will use in the rest of this work
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(one-electron reduced) density matrices
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(one-electron reduced) density matrices
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as basic variables, rather than Slater determinants. If we expand the
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as basic variables, rather than Slater determinants. If we expand the
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ensemble KS spinorbitals [from which the latter are constructed] in an atomic orbital (AO) basis,
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ensemble KS (spin) orbitals [from which the latter determinants are constructed] in an atomic orbital (AO) basis,
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\beq
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\beq
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\SO{p}{}(\br{}) = \sum_{\mu} \cMO{\mu p}{} \AO{\mu}(\br{}),
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\SO{p}{}(\br{}) = \sum_{\mu} \cMO{\mu p}{} \AO{\mu}(\br{}),
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\eeq
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\eeq
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then the density matrix elements obtained from the
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then the density matrix of the
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determinant $\Det{(K)}$ can be expressed as follows in the AO basis:
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determinant $\Det{(K)}$ can be expressed as follows in the AO basis:
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\beq
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\beq
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\bGam{(K)} \equiv \eGam{\mu\nu}{(K)} = \sum_{\SO{p}{} \in (K)} \cMO{\mu p}{} \cMO{\nu p}{},
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\bGam{(K)} \equiv \eGam{\mu\nu}{(K)} = \sum_{\SO{p}{} \in (K)} \cMO{\mu p}{} \cMO{\nu p}{},
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\eeq
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\eeq
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where the summation runs over the spinorbitals that are occupied in $\Det{(K)}$.
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where the summation runs over the spinorbitals that are occupied in
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Note that the density of the $K$th KS state reads
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$\Det{(K)}$. Note that, as the theory is applied later on to spin-polarized
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systems, we drop spin indices in the density matrices, for convenience.
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\manu{Is the latter sentence ok with you?}
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The electron density of the $K$th KS determinant can then be evaluated
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as follows:
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\beq
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\beq
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\n{\bGam{(K)}}{}(\br{}) = \sum_{\mu\nu} \AO{\mu}(\br{}) \eGam{\mu\nu}{(K)} \AO{\nu}(\br{}).
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\n{\bGam{(K)}}{}(\br{}) = \sum_{\mu\nu} \AO{\mu}(\br{}) \eGam{\mu\nu}{(K)} \AO{\nu}(\br{}),
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\eeq
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\eeq
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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% Manu's derivation %%%
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% Manu's derivation %%%
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@ -426,8 +430,8 @@ p}}c^\sigma_{{\nu p}}
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}
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}
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\fi%%%
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\fi%%%
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%%%% end Manu
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%%%% end Manu
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We can then construct the ensemble density matrix
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while the ensemble density matrix
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and the ensemble density as follows:
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and ensemble density read
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\beq
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\beq
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\bGam{\bw}
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\bGam{\bw}
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= \sum_{K\geq 0} \ew{K} \bGam{(K)}
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= \sum_{K\geq 0} \ew{K} \bGam{(K)}
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@ -439,7 +443,7 @@ and
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\n{\bGam{\bw}}{}(\br{}) = \sum_{\mu\nu} \AO{\mu}(\br{}) \eGam{\mu\nu}{\bw} \AO{\nu}(\br{}),
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\n{\bGam{\bw}}{}(\br{}) = \sum_{\mu\nu} \AO{\mu}(\br{}) \eGam{\mu\nu}{\bw} \AO{\nu}(\br{}),
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\eeq
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\eeq
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respectively.
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respectively.
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The exact expression of the individual energies in Eq.~\eqref{eq:exact_ener_level_dets} can then be rewritten as
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The individual energy expression in Eq.~\eqref{eq:exact_ener_level_dets} can then be rewritten as
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\beq\label{eq:exact_ind_ener_rdm}
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\beq\label{eq:exact_ind_ener_rdm}
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\begin{split}
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\begin{split}
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\E{}{(I)}
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\E{}{(I)}
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@ -460,7 +464,7 @@ where
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\bh \equiv h_{\mu\nu} = \mel*{\AO{\mu}}{\hh}{\AO{\nu}}
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\bh \equiv h_{\mu\nu} = \mel*{\AO{\mu}}{\hh}{\AO{\nu}}
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\eeq
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\eeq
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denotes the one-electron integrals matrix.
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denotes the one-electron integrals matrix.
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The individual Hx energy is obtained from the following trace formula
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The exact individual Hx energies are obtained from the following trace formula
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\beq
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\beq
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\Tr[\bGam{(K)} \bG \bGam{(L)}]
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\Tr[\bGam{(K)} \bG \bGam{(L)}]
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= \sum_{\mu\nu\la\si} \eGam{\mu\nu}{(K)} \eG{\mu\nu\la\si} \eGam{\la\si}{(L)},
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= \sum_{\mu\nu\la\si} \eGam{\mu\nu}{(K)} \eG{\mu\nu\la\si} \eGam{\la\si}{(L)},
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