Manu: gave the final expression for the individual energies
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@ -458,10 +458,34 @@ Hxc}(n^{\bw}(\br))\,n^{(I)}(\br)
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Hxc}(n)}{\partial n}\right|_{n=n^{\bw}(\br)}n^{\bw}(\br)\left(n^{(I)}(\br)-n^{\bw}(\br)\right)
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Hxc}(n)}{\partial n}\right|_{n=n^{\bw}(\br)}n^{\bw}(\br)\left(n^{(I)}(\br)-n^{\bw}(\br)\right)
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\nonumber\\
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\nonumber\\
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&&
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&&
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+\sum_{K>0}\left(\delta_{IK}-w^{(K)}\right)\left. \dfrac{\partial \overline{E}^{{\bw}}_{\rm
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+\int d\br\,\sum_{K>0}\left(\delta_{IK}-w^{(K)}\right)n^{{\bw}}(\br)\left.
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Hxc}\left[n\right]}{\partial w^{(K)}}\right|_{n=n^{{\bw}}}.
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\dfrac{\partial \overline{\epsilon}^{{\bw}}_{\rm
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Hxc}(n)}{\partial w^{(K)}}\right|_{n=n^{{\bw}}(\br)}.
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\eeq
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\eeq
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\alert{
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or, equivalently,
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\beq
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&&E^{(I)}\rightarrow
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{\rm
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Tr}\left[{\bmg}^{(I)}{\bm h}\right]+
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\Tr\left[\left(\bmg^{(I)}-\dfrac{1}{2}\bmg^{\bw}\right) \, \bG \, \bmg^{\bw}\right]
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\nonumber\\
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&&
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+\int d\br\,
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\dfrac{\delta \overline{E}^{{\bw}}_{\rm
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Hxc}\left[n^{\bw}\right]}{\delta
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n({\br})}\,n^{(I)}(\br)
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\nonumber\\
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&&
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-\int d\br\,\left.\dfrac{\partial \overline{\epsilon}^{{\bw}}_{\rm
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Hxc}(n)}{\partial n}\right|_{n=n^{\bw}(\br)}\Big(n^{\bw}(\br)\Big)^2
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\nonumber\\
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&&
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+\int d\br\,\sum_{K>0}\left(\delta_{IK}-w^{(K)}\right)n^{{\bw}}(\br)\left.
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\dfrac{\partial \overline{\epsilon}^{{\bw}}_{\rm
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Hxc}(n)}{\partial w^{(K)}}\right|_{n=n^{{\bw}}(\br)}.
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\eeq
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}
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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\subsection{KS-eDFT for excited states}
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\subsection{KS-eDFT for excited states}
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