Manu: done (so far) with the computational details
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@ -342,11 +342,21 @@ equals the exact ensemble one
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n^{\bw}(\br)=\sum_{I=0}^{\nEns-1}
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n^{\bw}(\br)=\sum_{I=0}^{\nEns-1}
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\ew{I}n_{\Psi_I}(\br).
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\ew{I}n_{\Psi_I}(\br).
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\eeq
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\eeq
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The minimizing density-functional KS
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In practice, the minimizing KS density matrix operator
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wavefunctions $\left\{\Det{I}{\bw}\left[n^{\bw}\right]\right\}_{0\leq
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$\hgam{\bw}\left[\n{}{\bw}\right]$
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I\leq M-1}$ are constructed from (weight-dependent) KS orbitals
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can be determined from the following KS reformulation of the
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GOK variational principle, \cite{Gross_1988b,Senjean_2015}
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\beq\label{eq:min_KS_DM}
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\E{}{\bw} = \min_{\hGam{\bw}} \left\{\Tr[\hGam{\bw}
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\left(\hT+\hVne\right)]+\E{\Ha}{}[\n{\hGam{\bw}}{}]+\E{\xc}{\bw}[\n{\hGam{\bw}}{}]\right\},
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\eeq
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where $\n{\hGam{\bw}}{}(\br)=\sum_{I=0}^{\nEns - 1}
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\ew{I}\n{\overline{\Psi}^{(I)}}{}$ is the trial ensemble density. As a
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result, the orbitals
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$\lbrace \MO{p}{\bw}(\br{}) \rbrace_{1 \le p \le
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$\lbrace \MO{p}{\bw}(\br{}) \rbrace_{1 \le p \le
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\nOrb}$. The latters are determined by solving the ensemble KS equation
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\nOrb}$ from which the KS
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wavefunctions $\left\{\Det{I}{\bw}\left[n^{\bw}\right]\right\}_{0\leq
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I\leq M-1}$ are constructed can be obtained by solving the following ensemble KS equation
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\begin{equation}
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\begin{equation}
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\label{eq:eKS}
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\label{eq:eKS}
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\qty{ \hHc(\br{}) + \fdv{\E{\Hxc}{\bw}[\n{}{\bw}]}{\n{}{}(\br{})}} \MO{p}{\bw}(\br{}) = \eps{p}{\bw} \MO{p}{\bw}(\br{}),
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\qty{ \hHc(\br{}) + \fdv{\E{\Hxc}{\bw}[\n{}{\bw}]}{\n{}{}(\br{})}} \MO{p}{\bw}(\br{}) = \eps{p}{\bw} \MO{p}{\bw}(\br{}),
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@ -491,8 +501,19 @@ This study deals only with spin-unpolarised systems, \ie, $\n{\uparrow}{} = \n{\
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Moreover, we restrict our study to the case of a two-state ensemble (\ie, $\nEns = 2$) where both the ground state ($I=0$ with weight $1 - \ew{}$) and the first doubly-excited state ($I=1$ with weight $\ew{}$) are considered.
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Moreover, we restrict our study to the case of a two-state ensemble (\ie, $\nEns = 2$) where both the ground state ($I=0$ with weight $1 - \ew{}$) and the first doubly-excited state ($I=1$ with weight $\ew{}$) are considered.
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Although one should have $0 \le \ew{} \le 1/2$ to ensure the GOK variational principle, we will sometimes ``violate'' this variational constraint.
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Although one should have $0 \le \ew{} \le 1/2$ to ensure the GOK variational principle, we will sometimes ``violate'' this variational constraint.
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Indeed, the limit $\ew{} = 1$ is of particular interest as it corresponds to a genuine saddle point of the KS equations, and match perfectly the results obtained with the maximum overlap method (MOM) developed by Gilbert, Gill and coworkers. \cite{Gilbert_2008,Barca_2018a,Barca_2018b}
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Indeed, the limit $\ew{} = 1$ is of particular interest as it corresponds to a genuine saddle point of the KS equations, and match perfectly the results obtained with the maximum overlap method (MOM) developed by Gilbert, Gill and coworkers. \cite{Gilbert_2008,Barca_2018a,Barca_2018b}
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\manu{Maybe we should be more clear about what we mean with $\ew{} = 1$.
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\manu{I think we need to be a bit more clear about the $\ew{} = 1$ case, as
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In the range $1/2\leq \ew{}\leq 1$, }
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it stands a little bit beyond the theory discussed previously. What you
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are looking at in the range $1/2\leq \ew{}\leq 1$ are, indeed, other
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stationary points (than the minimizing ones) of the density matrix
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operator functional in Eq.~(\ref{eq:min_KS_DM}). I would say that we
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look at these solutions for analysis purposes. I personally never looked
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(formally) at these solutions and their physical meaning. One should clearly
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mention that applying GOK-DFT in this range of weights would simply
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consists in switching ground and first excited states if a true
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minimization of the ensemble energy were performed. From this point of
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view we do not violate anything.
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}
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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\section{Results}
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\section{Results}
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\label{sec:res}
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\label{sec:res}
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