Merge overleaf-2020-02-06-1504 into master
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@ -247,7 +247,7 @@ In order to compute the neutral (optical) excitations of the system and their as
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\label{eq:BSE}
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\LBSE{}(1,2,1',2') = \LBSE{0}(1,2,1',2')
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\\
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+ \int d3 d4 d5 d6 \LBSE{0}(1,4,1',3) \XiBSE{}(3,5,4,6) \LBSE{}(6,2,5,2')
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+ \int d3 d4 d5 d6 \LBSE{0}(1,4,1',3) \XiBSE{}(3,5,4,6) \LBSE{}(6,2,5,2')
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\end{multline}
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as the linear response of the one-body Green's function $\G{}$ with respect to a general non-local external potential
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\begin{equation}
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