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qmckl/org/qmckl_examples.org

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Code examples

In this section, we present examples of usage of QMCkl. For simplicity, we assume that the wave function parameters are stored in a TREXIO file.

Python

Check numerically that MOs are orthonormal

In this example, we will compute numerically the overlap between the molecular orbitals:

\[ S_{ij} = \int \phi_i(\mathbf{r}) \phi_j(\mathbf{r}) \text{d}\mathbf{r} \sim \sum_{k=1}^{N} \phi_i(\mathbf{r}_k) \phi_j(\mathbf{r}_k) \delta \mathbf{r} \] \[ S_{ij} = \langle \phi_i | \phi_j \rangle \sim \sum_{k=1}^{N} \langle \phi_i | \mathbf{r}_k \rangle \langle \mathbf{r}_k | \phi_j \rangle \]

import numpy as np
import qmckl
trexio_filename = "..//share/qmckl/test_data/h2o_5z.h5"

context = qmckl.context_create()
qmckl.trexio_read(context, trexio_filename)

We now define the grid points $\mathbf{r}_k$ as a regular grid around the molecule.

We fetch the nuclear coordinates from the context,

nucl_num = qmckl.get_nucleus_num(context)

nucl_charge = qmckl.get_nucleus_charge(context, nucl_num)

nucl_coord = qmckl.get_nucleus_coord(context, 'N', nucl_num*3)
nucl_coord = np.reshape(nucl_coord, (3, nucl_num))

for i in range(nucl_num):
 print("%d  %+f %+f %+f"%(int(nucl_charge[i]),
                          nucl_coord[i,0],
                          nucl_coord[i,1],
                          nucl_coord[i,2]) )
8  +0.000000 +0.000000 +0.000000
1  -1.430429 +0.000000 -1.107157
1  +1.430429 +0.000000 -1.107157

and compute the coordinates of the grid points:

nx = ( 120, 120, 120 )
shift = np.array([5.,5.,5.])
point_num = nx[0] * nx[1] * nx[2]

rmin  = np.array( list([ np.min(nucl_coord[:,a]) for a in range(3) ]) )
rmax  = np.array( list([ np.max(nucl_coord[:,a]) for a in range(3) ]) )


linspace = [ None for i in range(3) ]
step     = [ None for i in range(3) ]
for a in range(3):
 linspace[a], step[a] = np.linspace(rmin[a]-shift[a],
                                    rmax[a]+shift[a],
                                    num=nx[a],
                                    retstep=True)

dr = step[0] * step[1] * step[2]
point = []
for x in linspace[0]:
 for y in linspace[1]:
     for z in linspace[2]:
         point += [ [x, y, z] ]

point = np.array(point)
point_num = len(point)
qmckl.set_point(context, 'N', point_num, np.reshape(point, (point_num*3)))

Then, we evaluate all the MOs at the grid points (and time the execution), and thus obtain the matrix $M_{ki} = \langle \mathbf{r}_k | \phi_i \rangle = \phi_i(\mathbf{r}_k)$.

import time

mo_num = qmckl.get_mo_basis_mo_num(context)

before   = time.time()
mo_value = qmckl.get_mo_basis_mo_value(context, point_num*mo_num)
after    = time.time()

mo_value = np.reshape( mo_value, (point_num, mo_num) )

print("Number of MOs: ", mo_num)
print("Number of grid points: ", point_num)
print("Execution time : ", (after - before), "seconds")
Number of MOs:  201
Number of grid points:  1728000
Execution time :  3.511528968811035 seconds

and finally we compute the overlap between all the MOs as $M^\dagger M$.

overlap = mo_value.T @ mo_value * dr
print (overlap)
[[ 9.88693941e-01  2.34719693e-03 -1.50518232e-08 ...  3.12084178e-09
  -5.81064929e-10  3.70130091e-02]
 [ 2.34719693e-03  9.99509628e-01  3.18930040e-09 ... -2.46888958e-10
  -1.06064273e-09 -7.65567973e-03]
 [-1.50518232e-08  3.18930040e-09  9.99995073e-01 ... -5.84882580e-06
  -1.21598117e-06  4.59036468e-08]
 ...
 [ 3.12084178e-09 -2.46888958e-10 -5.84882580e-06 ...  1.00019107e+00
  -2.03342837e-04 -1.36954855e-08]
 [-5.81064929e-10 -1.06064273e-09 -1.21598117e-06 ... -2.03342837e-04
   9.99262427e-01  1.18264754e-09]
 [ 3.70130091e-02 -7.65567973e-03  4.59036468e-08 ... -1.36954855e-08
   1.18264754e-09  8.97215950e-01]]

Fortran

Checking errors

All QMCkl functions return an error code. A convenient way to handle errors is to write an error-checking function that displays the error in text format and exits the program.

subroutine qmckl_check_error(rc, message)
use qmckl
implicit none
integer(qmckl_exit_code), intent(in) :: rc
character(len=*)        , intent(in) :: message
character(len=128)                   :: str_buffer
if (rc /= QMCKL_SUCCESS) then
  print *, message
  call qmckl_string_of_error(rc, str_buffer)
  print *, str_buffer
  call exit(rc)
end if
end subroutine qmckl_check_error

Computing an atomic orbital on a grid

The following program, in Fortran, computes the values of an atomic orbital on a regular 3-dimensional grid. The 100^3 grid points are automatically defined, such that the molecule fits in a box with 5 atomic units in the borders.

This program uses the qmckl_check_error function defined above.

To use this program, run

$ ao_grid <trexio_file> <AO_id> <point_num>
<<qmckl_check_error>>

program ao_grid
use qmckl
implicit none

integer(qmckl_context)    :: qmckl_ctx  ! QMCkl context
integer(qmckl_exit_code)  :: rc         ! Exit code of QMCkl functions

character(len=128)            :: trexio_filename
character(len=128)            :: str_buffer
integer                       :: ao_id
integer                       :: point_num_x

integer(c_int64_t)            :: nucl_num
double precision, allocatable :: nucl_coord(:,:)

integer(c_int64_t)            :: point_num
integer(c_int64_t)            :: ao_num
integer(c_int64_t)            :: ipoint, i, j, k
double precision              :: x, y, z, dr(3)
double precision              :: rmin(3), rmax(3)
double precision, allocatable :: points(:,:)
double precision, allocatable :: ao_vgl(:,:,:)

Start by fetching the command-line arguments:

if (iargc() /= 3) then
  print *, 'Syntax: ao_grid <trexio_file> <AO_id> <point_num>'
  call exit(-1)
end if
call getarg(1, trexio_filename)
call getarg(2, str_buffer)
read(str_buffer, *) ao_id
call getarg(3, str_buffer)
read(str_buffer, *) point_num_x

if (point_num_x < 0 .or. point_num_x > 300) then
  print *, 'Error: 0 < point_num < 300'
  call exit(-1)
end if

Create the QMCkl context and initialize it with the wave function present in the TREXIO file:

qmckl_ctx = qmckl_context_create()
rc  = qmckl_trexio_read(qmckl_ctx, trexio_filename, 1_8*len(trim(trexio_filename)))
call qmckl_check_error(rc, 'Read TREXIO')

We need to check that ao_id is in the range, so we get the total number of AOs from QMCkl:

rc = qmckl_get_ao_basis_ao_num(qmckl_ctx, ao_num)
call qmckl_check_error(rc, 'Getting ao_num')

if (ao_id < 0 .or. ao_id > ao_num) then
  print *, 'Error: 0 < ao_id < ', ao_num
  call exit(-1)
end if

Now we will compute the limits of the box in which the molecule fits. For that, we first need to ask QMCkl the coordinates of nuclei.

rc = qmckl_get_nucleus_num(qmckl_ctx, nucl_num)
call qmckl_check_error(rc, 'Get nucleus num')

allocate( nucl_coord(3, nucl_num) )
rc = qmckl_get_nucleus_coord(qmckl_ctx, 'N', nucl_coord, 3_8*nucl_num)
call qmckl_check_error(rc, 'Get nucleus coord')

We now compute the coordinates of opposite points of the box, and the distance between points along the 3 directions:

rmin(1) = minval( nucl_coord(1,:) ) - 5.d0
rmin(2) = minval( nucl_coord(2,:) ) - 5.d0
rmin(3) = minval( nucl_coord(3,:) ) - 5.d0
  
rmax(1) = maxval( nucl_coord(1,:) ) + 5.d0
rmax(2) = maxval( nucl_coord(2,:) ) + 5.d0
rmax(3) = maxval( nucl_coord(3,:) ) + 5.d0

dr(1:3) = (rmax(1:3) - rmin(1:3)) / dble(point_num_x-1)

We now produce the list of point coordinates where the AO will be evaluated:

point_num = point_num_x**3
allocate( points(point_num, 3) )
ipoint=0
z = rmin(3)
do k=1,point_num_x
  y = rmin(2)
  do j=1,point_num_x
     x = rmin(1)
     do i=1,point_num_x
        ipoint = ipoint+1
        points(ipoint,1) = x
        points(ipoint,2) = y
        points(ipoint,3) = z
        x = x + dr(1)
     end do
     y = y + dr(2)
  end do
  z = z + dr(3)
end do

We give the points to QMCkl:

rc = qmckl_set_point(qmckl_ctx, 'T', point_num, points, size(points)*1_8 )
call qmckl_check_error(rc, 'Setting points')

We allocate the space required to retrieve the values, gradients and Laplacian of all AOs, and ask to retrieve the values of the AOs computed at the point positions.

allocate( ao_vgl(ao_num, 5, point_num) )
rc = qmckl_get_ao_basis_ao_vgl(qmckl_ctx, ao_vgl, ao_num*5_8*point_num)
call qmckl_check_error(rc, 'Setting points')

We finally print the value and Laplacian of the AO:

do ipoint=1, point_num
  print '(3(F10.6,X),2(E20.10,X))', points(ipoint, 1:3), ao_vgl(ao_id,1,ipoint), ao_vgl(ao_id,5,ipoint)
end do
deallocate( nucl_coord, points, ao_vgl )
end program ao_grid