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Update PDMC

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Anthony Scemama 2021-02-02 23:41:07 +01:00
parent 5aeb6c3c92
commit c10c7697b9

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@ -2235,10 +2235,11 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
where $\chi$ is a Gaussian random variable, and the potential term
can be simulated by creating or destroying particles over time (a
so-called branching process) or by simply considering it as a
cumulative multiplicative weight along the diffusion trajectory:
cumulative multiplicative weight along the diffusion trajectory
(pure Diffusion Monte Carlo):
\[
\exp \left( \int_0^\tau - (E_L(\mathbf{r}_t) - E_{\text{ref}}) dt \right)
\exp \left( \int_0^\tau - (V(\mathbf{r}_t) - E_{\text{ref}}) dt \right).
\]
@ -2260,7 +2261,7 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
In a molecular system, the potential is far from being constant
and, in fact, diverges at the inter-particle coalescence points. Hence,
it results in very large fluctuations of the term associated with
it results in very large fluctuations of the erm weight associated with
the potental, making the calculations impossible in practice.
Fortunately, if we multiply the Schrödinger equation by a chosen
/trial wave function/ $\Psi_T(\mathbf{r})$ (Hartree-Fock, Kohn-Sham
@ -2284,17 +2285,19 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
scheme presented in the previous section (VMC).
The new "potential" is the local energy, which has smaller fluctuations
when $\Psi_T$ gets closer to the exact wave function.
This term can be simulated by t particles according to $\exp\left[ -\delta t\,
\left(E_L(\mathbf{r}) - E_{\rm ref}\right)\right]$
This term can be simulated by
\[
\exp \left( \int_0^\tau - (E_L(\mathbf{r}_t) - E_{\text{ref}}) dt \right).
\]
where $E_{\rm ref}$ is the constant we had introduced above, which is adjusted to
the running average energy to keep the number of particles
reasonably constant.
an estimate of the average energy to keep the weights close to one.
This equation generates the /N/-electron density $\Pi$, which is the
product of the ground state with the trial wave function. You may then ask: how
can we compute the total energy of the system?
product of the ground state solution with the trial wave
function. You may then ask: how can we compute the total energy of
the system?
To this aim, we use the mixed estimator of the energy:
To this aim, we use the /mixed estimator/ of the energy:
\begin{eqnarray*}
E(\tau) &=& \frac{\langle \psi(\tau) | \hat{H} | \Psi_T \rangle}{\langle \psi(\tau) | \Psi_T \rangle}\\
@ -2310,7 +2313,8 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
\Pi(\mathbf{r},\tau) =\psi(\mathbf{r},\tau) \Psi_T(\mathbf{r}) \rightarrow \Phi_0(\mathbf{r}) \Psi_T(\mathbf{r})\,,
\]
and, using that $\hat{H}$ is Hermitian and that $\Phi_0$ is an eigenstate of the Hamiltonian, we obtain for large $\tau$
and, using that $\hat{H}$ is Hermitian and that $\Phi_0$ is an
eigenstate of the Hamiltonian, we obtain for large $\tau$
\[
E(\tau) = \frac{\langle \psi_\tau | \hat{H} | \Psi_T \rangle}
@ -2372,12 +2376,12 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
\right] + E_L(\mathbf{r}) \Pi(\mathbf{r},\tau)
\]
** Pure Diffusion Monte Carlo (PDMC)
** Pure Diffusion Monte Carlo
Instead of having a variable number of particles to simulate the
branching process, one can consider the term
$\exp \left( -\delta t\,( E_L(\mathbf{r}) - E_{\rm ref}) \right)$ as a
cumulative product of weights:
branching process as in the /Diffusion Monte Carlo/ (DMC) algorithm, we
use variant called /pure Diffusion Monte Carlo/ (PDMC) where
the potential term is considered as a cumulative product of weights:
\begin{eqnarray*}
W(\mathbf{r}_n, \tau)
@ -2387,21 +2391,39 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
\prod_{i=1}^{n} w(\mathbf{r}_i)
\end{eqnarray*}
where $\mathbf{r}_i$ are the coordinates along the trajectory and we introduced a time-step $\delta t$.
The algorithm can be rather easily built on top of your VMC code:
where $\mathbf{r}_i$ are the coordinates along the trajectory and
we introduced a /time-step variable/ $\delta t$ to discretize the
integral.
0) Start with $W=1$
1) Evaluate the local energy at $\mathbf{r}_{n}$ and accumulate it
2) Compute the weight $w(\mathbf{r}_n)$
3) Update $W$
4) Compute a new position $\mathbf{r'} = \mathbf{r}_n +
The PDMC algorithm is less stable than the DMC algorithm: it
requires to have a value of $E_\text{ref}$ which is close to the
fixed-node energy, and a good trial wave function. Moreover, we
can't let $\tau$ become too large because the weight whether
explode or vanish: we need to have a fixed value of $\tau$
(projection time).
The big advantage of PDMC is that it is rather simple to implement
starting from a VMC code:
0) Start with $W(\mathbf{r}_0)=1, \tau_0 = 0$
1) Evaluate the local energy at $\mathbf{r}_{n}$
2) Compute the contribution to the weight $w(\mathbf{r}_n) =
\exp(-\delta t(E_L(\mathbf{r}_n)-E_\text{ref}))$
3) Update $W(\mathbf{r}_{n}) = W(\mathbf{r}_{n-1}) \times w(\mathbf{r}_n)$
4) Accumulate the weighted energy $W(\mathbf{r}_n) \times
E_L(\mathbf{r}_n)$,
and the weight $W(\mathbf{r}_n)$ for the normalization
5) Update $\tau_n = \tau_{n-1} + \delta t$
6) If $\tau_{n} > \tau_\text{max}$, the long projection time has
been reached and we can start an new trajectory from the current
position: reset $W(r_n) = 1$ and $\tau_n
= 0$
7) Compute a new position $\mathbf{r'} = \mathbf{r}_n +
\delta t\, \frac{\nabla \Psi(\mathbf{r})}{\Psi(\mathbf{r})} + \chi$
5) Evaluate $\Psi(\mathbf{r}')$ and $\frac{\nabla \Psi(\mathbf{r'})}{\Psi(\mathbf{r'})}$ at the new position
6) Compute the ratio $A = \frac{T(\mathbf{r}' \rightarrow \mathbf{r}_{n}) P(\mathbf{r}')}{T(\mathbf{r}_{n} \rightarrow \mathbf{r}') P(\mathbf{r}_{n})}$
7) Draw a uniform random number $v \in [0,1]$
8) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
9) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
8) Evaluate $\Psi(\mathbf{r}')$ and $\frac{\nabla \Psi(\mathbf{r'})}{\Psi(\mathbf{r'})}$ at the new position
9) Compute the ratio $A = \frac{T(\mathbf{r}' \rightarrow \mathbf{r}_{n}) P(\mathbf{r}')}{T(\mathbf{r}_{n} \rightarrow \mathbf{r}') P(\mathbf{r}_{n})}$
10) Draw a uniform random number $v \in [0,1]$
11) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
12) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
Some comments are needed:
@ -2412,19 +2434,16 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
E = \frac{\sum_{k=1}^{N_{\rm MC}} E_L(\mathbf{r}_k) W(\mathbf{r}_k, k\delta t)}{\sum_{k=1}^{N_{\rm MC}} W(\mathbf{r}_k, k\delta t)}
\end{eqnarray*}
- The result will be affected by a time-step error (the finite size of $\delta t$) and one
has in principle to extrapolate to the limit $\delta t \rightarrow 0$. This amounts to fitting
the energy computed for multiple values of $\delta t$.
- The result will be affected by a time-step error
(the finite size of $\delta t$) due to the discretization of the
integral, and one has in principle to extrapolate to the limit
$\delta t \rightarrow 0$. This amounts to fitting the energy
computed for multiple values of $\delta t$.
Here, you will be using a small enough time-step and you should not worry about the extrapolation.
- The accept/reject step (steps 2-5 in the algorithm) is in principle not needed for the correctness of
- The accept/reject step (steps 9-12 in the algorithm) is in principle not needed for the correctness of
the DMC algorithm. However, its use reduces significantly the time-step error.
The PDMC algorithm is less stable than the branching algorithm: it
requires to have a value of $E_\text{ref}$ which is close to the
fixed-node energy, and a good trial wave function. Its big
advantage is that it is very easy to program starting from a VMC
code, so this is what we will do in the next section.
** Hydrogen atom
:PROPERTIES:
@ -2435,9 +2454,10 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
*** Exercise
#+begin_exercise
Modify the Metropolis VMC program to introduce the PDMC weight.
Modify the Metropolis VMC program into a PDMC program.
In the limit $\delta t \rightarrow 0$, you should recover the exact
energy of H for any value of $a$.
energy of H for any value of $a$, as long as the simulation is stable.
We choose here a fixed projection time $\tau=10$ a.u.
#+end_exercise
*Python*
@ -2452,6 +2472,7 @@ def MonteCarlo(a, nmax, dt, Eref):
a = 1.2
nmax = 100000
dt = 0.01
tau = 10.
E_ref = -0.5
X0 = [ MonteCarlo(a, nmax, dt, E_ref) for i in range(30)]
@ -2467,6 +2488,8 @@ A, deltaA = ave_error(X)
print(f"A = {A} +/- {deltaA}")
#+END_SRC
#+RESULTS:
*Fortran*
#+BEGIN_SRC f90 :tangle none
subroutine pdmc(a, dt, nmax, energy, accep, tau, E_ref)