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Compute E_L before moving, and fix bug in Python code
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QMC.org
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QMC.org
@ -1424,13 +1424,13 @@ gfortran hydrogen.f90 qmc_stats.f90 qmc_uniform.f90 -o qmc_uniform
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The algorithm is summarized as follows:
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1) Compute $\Psi$ at a new position $\mathbf{r'} = \mathbf{r}_n +
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\delta L\, \mathbf{u}$
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2) Compute the ratio $A = \frac{\left|\Psi(\mathbf{r'})\right|^2}{\left|\Psi(\mathbf{r}_{n})\right|^2}$
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3) Draw a uniform random number $v \in [0,1]$
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4) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
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5) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
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6) evaluate the local energy at $\mathbf{r}_{n+1}$
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1) Evaluate the local energy at $\mathbf{r}_n$ and accumulate it
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2) Compute a new position $\mathbf{r'} = \mathbf{r}_n + \delta L\, \mathbf{u}$
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3) Evaluate $\Psi(\mathbf{r}')$ at the new position
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4) Compute the ratio $A = \frac{\left|\Psi(\mathbf{r'})\right|^2}{\left|\Psi(\mathbf{r}_{n})\right|^2}$
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5) Draw a uniform random number $v \in [0,1]$
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6) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
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7) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
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#+begin_note
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A common error is to remove the rejected samples from the
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@ -1742,7 +1742,7 @@ gfortran hydrogen.f90 qmc_stats.f90 qmc_metropolis.f90 -o qmc_metropolis
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Furthermore, to sample the density even better, we can "push" the electrons
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into in the regions of high probability, and "pull" them away from
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the low-probability regions. This will ncrease the
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the low-probability regions. This will increase the
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acceptance ratios and improve the sampling.
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To do this, we can use the gradient of the probability density
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@ -1761,7 +1761,7 @@ gfortran hydrogen.f90 qmc_stats.f90 qmc_metropolis.f90 -o qmc_metropolis
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\Psi(\mathbf{r}_n)}{\Psi(\mathbf{r}_n)} \right)^2}{2\,\delta t} \right]\,.
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\]
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The corrsponding move is proposed as
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The corresponding move is proposed as
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\[
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\mathbf{r}_{n+1} = \mathbf{r}_{n} + \delta t\, \frac{\nabla
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@ -1775,15 +1775,14 @@ gfortran hydrogen.f90 qmc_stats.f90 qmc_metropolis.f90 -o qmc_metropolis
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The algorithm of the previous exercise is only slighlty modified as:
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1) Compute a new position $\mathbf{r'} = \mathbf{r}_n +
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1) Evaluate the local energy at $\mathbf{r}_{n}$ and accumulate it
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2) Compute a new position $\mathbf{r'} = \mathbf{r}_n +
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\delta t\, \frac{\nabla \Psi(\mathbf{r})}{\Psi(\mathbf{r})} + \chi$
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Evaluate $\Psi$ and $\frac{\nabla \Psi(\mathbf{r})}{\Psi(\mathbf{r})}$ at the new position
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2) Compute the ratio $A = \frac{T(\mathbf{r}_{n+1} \rightarrow \mathbf{r}_{n}) P(\mathbf{r}_{n+1})}{T(\mathbf{r}_{n} \rightarrow \mathbf{r}_{n+1}) P(\mathbf{r}_{n})}$
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3) Draw a uniform random number $v \in [0,1]$
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4) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
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5) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
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6) evaluate the local energy at $\mathbf{r}_{n+1}$
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3) Evaluate $\Psi(\mathbf{r}')$ and $\frac{\nabla \Psi(\mathbf{r'})}{\Psi(\mathbf{r'})}$ at the new position
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4) Compute the ratio $A = \frac{T(\mathbf{r}' \rightarrow \mathbf{r}_{n}) P(\mathbf{r}')}{T(\mathbf{r}_{n} \rightarrow \mathbf{r}') P(\mathbf{r}_{n})}$
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5) Draw a uniform random number $v \in [0,1]$
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6) if $v \le A$, accept the move : set $\mathbf{r}_{n+1} = \mathbf{r'}$
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7) else, reject the move : set $\mathbf{r}_{n+1} = \mathbf{r}_n$
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*** Gaussian random number generator
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@ -1840,6 +1839,11 @@ end subroutine random_gauss
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*** Exercise 1
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#+begin_exercise
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If you use Fortran, copy/paste the ~random_gauss~ function in
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a Fortran file.
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#+end_exercise
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#+begin_exercise
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Write a function to compute the drift vector $\frac{\nabla \Psi(\mathbf{r})}{\Psi(\mathbf{r})}$.
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#+end_exercise
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@ -2014,13 +2018,13 @@ def MonteCarlo(a,nmax,dt):
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d2_old = d2_new
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psi_old = psi_new
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return energy/nmax, accep_rate/nmax
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return energy/nmax, N_accep/nmax
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# Run simulation
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a = 1.2
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nmax = 100000
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dt = 1.3
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dt = 1.0
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X0 = [ MonteCarlo(a,nmax,dt) for i in range(30)]
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@ -2036,8 +2040,6 @@ print(f"A = {A} +/- {deltaA}")
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#+END_SRC
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#+RESULTS:
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: E = -0.4951317910667116 +/- 0.00014045774335059988
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: A = 0.7200673333333333 +/- 0.00045942791345632793
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*Fortran*
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#+BEGIN_SRC f90
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@ -2144,8 +2146,8 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc_metropolis.f90 -o vmc_metropolis
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#+end_src
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#+RESULTS:
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: E = -0.49497258331144794 +/- 1.0973395750688713E-004
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: A = 0.78839866666666658 +/- 3.2503783452043152E-004
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: E = -0.47940635575542706 +/- 5.5613594433433764E-004
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: A = 0.62037333333333333 +/- 4.8970160591451110E-004
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* Diffusion Monte Carlo :solution:
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@ -3099,4 +3101,5 @@ gfortran hydrogen.f90 qmc_stats.f90 vmc.f90 -o vmc
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| <2021-02-04 Thu 14:00-14:10> | 3.1 |
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| <2021-02-04 Thu 14:10-14:30> | 3.2 |
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| <2021-02-04 Thu 14:30-15:30> | 3.3 |
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| <2021-02-04 Thu 15:30-16:30> | 3.4 |
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|------------------------------+---------|
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@ -45,7 +45,7 @@ def MonteCarlo(a,nmax,dt):
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# Run simulation
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a = 1.2
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nmax = 100000
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dt = 1.3
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dt = 1.0
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X0 = [ MonteCarlo(a,nmax,dt) for i in range(30)]
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