fix issue with phi
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@ -249,7 +249,7 @@ This evidences that encircling non-Hermitian degeneracies at EPs leads to an int
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The eigenvectors associated to the eigenenergies \eqref{eq:E_2x2} are
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\begin{equation}\label{eq:phi_2x2}
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\begin{split}
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\phi_{\pm}(\lambda)
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\phi_{\pm}
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& =
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\begin{pmatrix}
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(\epsilon_1 - \epsilon_2 \pm \sqrt{(\epsilon_1 - \epsilon_2)^2 + 4\lambda^2})/2\lambda
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@ -267,9 +267,9 @@ The eigenvectors associated to the eigenenergies \eqref{eq:E_2x2} are
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\end{equation}
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and, for $\lambda=\lambda_\text{EP}$, they become
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\begin{align}
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\phi_{\pm}\qty(i\,\frac{\epsilon_1 - \epsilon_2}{2}) & = \begin{pmatrix} -i \\ 1\end{pmatrix},
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\phi_{\pm} & = \begin{pmatrix} -i \\ 1\end{pmatrix},
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&
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\phi_{\pm}\qty(-i\,\frac{\epsilon_1 - \epsilon_2}{2}) & = \begin{pmatrix} i \\ 1\end{pmatrix}.
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\phi_{\pm} & = \begin{pmatrix} i \\ 1\end{pmatrix},
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\end{align}
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which are clearly self-orthogonal, i.e., their norm is equal to zero.
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%Using Eq.~\eqref{eq:E_EP}, Eq.~\eqref{eq:phi_2x2} can be recast as
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@ -282,7 +282,7 @@ Then, if the eigenvectors are properly normalized, they behave as $(\lambda - \l
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\phi_{\pm}(2\pi) & = \phi_{\mp}(0),
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&
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\phi_{\pm}(4\pi) & = -\phi_{\pm}(0),
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\\
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&
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\phi_{\pm}(6\pi) & = -\phi_{\mp}(0),
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&
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\phi_{\pm}(8\pi) & = \phi_{\pm}(0).
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@ -349,6 +349,7 @@ is the core Hamiltonian and
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v^\text{HF}(\vb{x}) = \sum_i \qty[ J_i(\vb{x}) - K_i(\vb{x}) ]
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\end{equation}
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is the HF mean-field potential with
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\begin{subequations}
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\begin{gather}
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\label{eq:CoulOp}
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J_i(\vb{x})\phi_p(\vb{x})=\qty[\int\dd\vb{x}'\phi_i(\vb{x}')\frac{1}{\abs{\vb{r} - \vb{r}'}}\phi_i(\vb{x}') ] \phi_p(\vb{x})
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@ -356,6 +357,7 @@ is the HF mean-field potential with
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\label{eq:ExcOp}
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K_i(\vb{x})\phi_p(\vb{x})=\qty[\int\dd\vb{x}'\phi_i(\vb{x}')\frac{1}{\abs{\vb{r} - \vb{r}'}}\phi_p(\vb{x}') ] \phi_i(\vb{x})
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\end{gather}
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\end{subequations}
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being the Coulomb and exchange operators (respectively) in the spin-orbital basis.
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From hereon, $i$ and $j$ are occupied orbitals, $a$ and $b$ are unoccupied (or virtual) orbitals, while $p$, $q$, $r$, and $s$ indicate arbitrary orbitals.
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Rather than solving Eq.~\eqref{eq:SchrEq}, HF theory uses the variational principle to find an approximation of $\Psi$ as a single Slater determinant. Hence a Slater determinant is not an eigenfunction of the exact Hamiltonian $\hH$. However, it is, by definition, an eigenfunction of the so-called (approximated) HF many-electron Hamiltonian defined as the sum of the one-electron Fock operators
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