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@ -484,7 +484,7 @@ the spin-$\sigma$ electrons as
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In the weak correlation regime $0 \le U \le 2t$, the angles which minimise the HF energy,
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\ie, $\pdv*{E_\text{HF}}{\theta_\sigma} = 0$, are
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\begin{equation}
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\ta^\text{RHF} = \tb^\text{RHF} = \pi/4,
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\ta^\text{RHF} = \tb^\text{RHF} = \pi/2,
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\end{equation}
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giving the symmetry-pure molecular orbitals
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\begin{align}
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